zs

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

受欢迎的三角函数 >

2cos(x)+sqrt(3)=0,0<= x<= 2pi

解答

2 cos (x) + 3 = 0, 0 \leq x \leq 2 π

解答

x = \frac{5 π}{6}, x = \frac{7 π}{6}

+1

度数

x = 15 0^{\circ}, x = 21 0^{\circ}

求解步骤

2 cos (x) + 3 = 0, 0 \leq x \leq 2 π

将

3

到右边

2 cos (x) + 3 = 0

两边减去

3

2 cos (x) + 3 - 3 = 0 - 3

化简

2 cos (x) = - 3

2 cos (x) = - 3

两边除以

2

2 cos (x) = - 3

两边除以

2

\frac{2 cos ( x )}{2} = \frac{- 3}{2}

化简

cos (x) = - \frac{3}{2}

cos (x) = - \frac{3}{2}

cos (x) = - \frac{3}{2}

的通解

cos (x)

周期表（周期为

2 πn

）：

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} cos (x) 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} x π \frac{7 π}{6} \frac{5 π}{4} \frac{4 π}{3} \frac{3 π}{2} \frac{5 π}{3} \frac{7 π}{4} \frac{11 π}{6} cos (x) - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2} 0 \frac{1}{2} \frac{2}{2} \frac{3}{2}

x = \frac{5 π}{6} + 2 πn, x = \frac{7 π}{6} + 2 πn

x = \frac{5 π}{6} + 2 πn, x = \frac{7 π}{6} + 2 πn

在

0 \leq x \leq 2 π

范围内的解

x = \frac{5 π}{6}, x = \frac{7 π}{6}

作图

流行的例子

(cot^2(x))/(1+sin(x))=(csc(x)-1)/(sin^2(x))

\frac{cot ^{2} ( x )}{1 + sin ( x )} = \frac{csc ( x ) - 1}{sin ^{2} ( x )}

tan (x) = 2.3

2sec^2(x)=5tan(x)+5

2 sec^{2} (x) = 5 tan (x) + 5

solvefor x,y=arcsin(xy)

so l v e f or x, y = arcsin (x y)

2sin^3(x/2)cos(x/2)=cos^2(x/2)sin(x)

2 sin^{3} (\frac{x}{2}) cos (\frac{x}{2}) = cos^{2} (\frac{x}{2}) sin (x)