zs

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

受欢迎的三角函数 >

cos(1/2 x)=-1

解答

cos (\frac{1}{2} x) = - 1

解答

x = 2 π + 4 πn

+1

度数

x = 36 0^{\circ} + 72 0^{\circ} n

求解步骤

cos (\frac{1}{2} x) = - 1

cos (\frac{1}{2} x) = - 1

的通解

cos (x)

周期表（周期为

2 πn

）：

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} cos (x) 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} x π \frac{7 π}{6} \frac{5 π}{4} \frac{4 π}{3} \frac{3 π}{2} \frac{5 π}{3} \frac{7 π}{4} \frac{11 π}{6} cos (x) - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2} 0 \frac{1}{2} \frac{2}{2} \frac{3}{2}

\frac{1}{2} x = π + 2 πn

\frac{1}{2} x = π + 2 πn

解

\frac{1}{2} x = π + 2 πn : x = 2 π + 4 πn

\frac{1}{2} x = π + 2 πn

在两边乘以

2

\frac{1}{2} x = π + 2 πn

在两边乘以

2

2 \cdot \frac{1}{2} x = 2 π + 2 \cdot 2 πn

化简

x = 2 π + 4 πn

x = 2 π + 4 πn

x = 2 π + 4 πn

作图

流行的例子

(-(3*cos(Q^1)))/2 =0

\frac{- ( 3 \cdot cos ( Q ^{1} ) )}{2} = 0

tan^2(x)+sqrt(3)tan(x)=0,0<= x<360

tan^{2} (x) + 3 tan (x) = 0, 0^{\circ} \leq x < 36 0^{\circ}

1/2 (6.50941)+cos(θ)(10.40478)=12

\frac{1}{2} (6.50941) + cos (θ) (10.40478) = 12

- 8 = - 4 + 4 tan (θ)

cos (x) = 0.2588