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受欢迎的三角函数 >

-arctan(t)=(4-pi)/4

解答

- arctan (t) = \frac{4 - π}{4}

解答

t = - tan (\frac{4 - π}{4})

求解步骤

- arctan (t) = \frac{4 - π}{4}

两边除以

- 1

- arctan (t) = \frac{4 - π}{4}

两边除以

- 1

\frac{- arctan ( t )}{- 1} = \frac{\frac{4 - π}{4}}{- 1}

化简

\frac{- arctan ( t )}{- 1} = \frac{\frac{4 - π}{4}}{- 1}

化简

\frac{- arctan ( t )}{- 1} : arctan (t)

\frac{- arctan ( t )}{- 1}

使用分式法则:

\frac{- a}{- b} = \frac{a}{b}

= \frac{arctan ( t )}{1}

使用法则

\frac{a}{1} = a

= arctan (t)

化简

\frac{\frac{4 - π}{4}}{- 1} : - \frac{4 - π}{4}

\frac{\frac{4 - π}{4}}{- 1}

使用分式法则:

\frac{a}{- b} = - \frac{a}{b}

= - \frac{\frac{4 - π}{4}}{1}

使用分式法则:

\frac{a}{1} = a

\frac{\frac{4 - π}{4}}{1} = \frac{4 - π}{4}

= - \frac{4 - π}{4}

arctan (t) = - \frac{4 - π}{4}

arctan (t) = - \frac{4 - π}{4}

arctan (t) = - \frac{4 - π}{4}

使用反三角函数性质

arctan (t) = - \frac{4 - π}{4}

arctan (x) = a \Rightarrow x = tan (a)

t = tan (- \frac{4 - π}{4})

tan (- \frac{4 - π}{4}) = - tan (\frac{4 - π}{4})

tan (- \frac{4 - π}{4})

利用以下特性:

tan (- x) = - tan (x)

tan (- \frac{4 - π}{4}) = - tan (\frac{4 - π}{4})

= - tan (\frac{4 - π}{4})

t = - tan (\frac{4 - π}{4})

t = - tan (\frac{4 - π}{4})

作图

流行的例子

cos^2(x+30)= 1/4

cos^{2} (x + 3 0^{\circ}) = \frac{1}{4}

cos (5 7^{\circ}) = sin (x)

3cos(x)=2-cos(x)

3 cos (x) = 2 - cos (x)

2cos^2(3x)-3cos(3x)=-1,0<= x<= 2pi

2 cos^{2} (3 x) - 3 cos (3 x) = - 1, 0 \leq x \leq 2 π

solvefor x,z=y^{sin(x)}

so l v e f or x, z = y^{s i n (x)}