y^{''}+y=csc^2(x)

Lösung

y^{^{''}} + y = csc^{2} (x)

y = c_{1} cos (x) + c_{2} sin (x) - cos (x) ln (tan (\frac{x}{2})) - 1

Schritte zur Lösung

y^{''} (x) + y = csc^{2} (x)

Solve linear ODE:

y = c_{1} cos (x) + c_{2} sin (x) - cos (x) ln (tan (\frac{x}{2})) - 1

y = c_{1} cos (x) + c_{2} sin (x) - cos (x) ln (tan (\frac{x}{2})) - 1

\int x (x^{2} + 1)^{4} d x

\frac{d}{d x} (\frac{x - 1}{x + 1})

\frac{\partial}{\partial x} (\frac{1}{2} ln (x + y))

y^{^{''}} + k^{2} y = 0

\int sec^{4} (5 x) tan^{6} (5 x) d x