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Popular Trigonometry >

-cos(3x)<0

  • Pre Algebra
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Solution

−cos(3x)<0

Solution

−6π​+32π​n<x<6π​+32π​n
+2
Interval Notation
(−6π​+32π​n,6π​+32π​n)
Decimal
−0.52359…+32π​n<x<0.52359…+32π​n
Solution steps
−cos(3x)<0
Multiply both sides by −1
−cos(3x)<0
Multiply both sides by -1 (reverse the inequality)(−cos(3x))(−1)>0⋅(−1)
Simplifycos(3x)>0
cos(3x)>0
For cos(x)>a, if −1≤a<1 then −arccos(a)+2πn<x<arccos(a)+2πn−arccos(0)+2πn<3x<arccos(0)+2πn
If a<u<bthen a<uandu<b−arccos(0)+2πn<3xand3x<arccos(0)+2πn
−arccos(0)+2πn<3x:x>−6π​+32πn​
−arccos(0)+2πn<3x
Switch sides3x>−arccos(0)+2πn
Simplify −arccos(0)+2πn:−2π​+2πn
−arccos(0)+2πn
Use the following trivial identity:arccos(0)=2π​x−1−23​​−22​​−21​021​22​​23​​1​arccos(x)π65π​43π​32π​2π​3π​4π​6π​0​arccos(x)180∘150∘135∘120∘90∘60∘45∘30∘0∘​​=−2π​+2πn
3x>−2π​+2πn
Divide both sides by 3
3x>−2π​+2πn
Divide both sides by 333x​>−32π​​+32πn​
Simplify
33x​>−32π​​+32πn​
Simplify 33x​:x
33x​
Divide the numbers: 33​=1=x
Simplify −32π​​+32πn​:−6π​+32πn​
−32π​​+32πn​
32π​​=6π​
32π​​
Apply the fraction rule: acb​​=c⋅ab​=2⋅3π​
Multiply the numbers: 2⋅3=6=6π​
=−6π​+32πn​
x>−6π​+32πn​
x>−6π​+32πn​
x>−6π​+32πn​
3x<arccos(0)+2πn:x<6π​+32πn​
3x<arccos(0)+2πn
Simplify arccos(0)+2πn:2π​+2πn
arccos(0)+2πn
Use the following trivial identity:arccos(0)=2π​x−1−23​​−22​​−21​021​22​​23​​1​arccos(x)π65π​43π​32π​2π​3π​4π​6π​0​arccos(x)180∘150∘135∘120∘90∘60∘45∘30∘0∘​​=2π​+2πn
3x<2π​+2πn
Divide both sides by 3
3x<2π​+2πn
Divide both sides by 333x​<32π​​+32πn​
Simplify
33x​<32π​​+32πn​
Simplify 33x​:x
33x​
Divide the numbers: 33​=1=x
Simplify 32π​​+32πn​:6π​+32πn​
32π​​+32πn​
32π​​=6π​
32π​​
Apply the fraction rule: acb​​=c⋅ab​=2⋅3π​
Multiply the numbers: 2⋅3=6=6π​
=6π​+32πn​
x<6π​+32πn​
x<6π​+32πn​
x<6π​+32πn​
Combine the intervalsx>−6π​+32πn​andx<6π​+32πn​
Merge Overlapping Intervals−6π​+32π​n<x<6π​+32π​n

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