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受欢迎的三角函数 >

15=25+2sqrt(100)cos(x)

解答

15 = 25 + 2 \cdot 100 \cdot cos (x)

解答

x = \frac{2 π}{3} + 2 πn, x = \frac{4 π}{3} + 2 πn

+1

度数

x = 12 0^{\circ} + 36 0^{\circ} n, x = 24 0^{\circ} + 36 0^{\circ} n

求解步骤

15 = 25 + 2100 cos (x)

交换两边

25 + 2100 cos (x) = 15

2100 cos (x) = 20 cos (x)

2100 cos (x)

100 = 10

100

因式分解数字:

100 = 1 0^{2}

= 1 0^{2}

使用根式运算法则:

n a^{n} = a

1 0^{2} = 10

= 10

= 2 \cdot 10 cos (x)

数字相乘:

2 \cdot 10 = 20

= 20 cos (x)

25 + 20 cos (x) = 15

将

25

到右边

25 + 20 cos (x) = 15

两边减去

25

25 + 20 cos (x) - 25 = 15 - 25

化简

20 cos (x) = - 10

20 cos (x) = - 10

两边除以

20

20 cos (x) = - 10

两边除以

20

\frac{20 cos ( x )}{20} = \frac{- 10}{20}

化简

\frac{20 cos ( x )}{20} = \frac{- 10}{20}

化简

\frac{20 cos ( x )}{20} : cos (x)

\frac{20 cos ( x )}{20}

数字相除:

\frac{20}{20} = 1

= cos (x)

化简

\frac{- 10}{20} : - \frac{1}{2}

\frac{- 10}{20}

使用分式法则:

\frac{- a}{b} = - \frac{a}{b}

= - \frac{10}{20}

约分:

10

= - \frac{1}{2}

cos (x) = - \frac{1}{2}

cos (x) = - \frac{1}{2}

cos (x) = - \frac{1}{2}

cos (x) = - \frac{1}{2}

的通解

cos (x)

周期表（周期为

2 πn

）：

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} cos (x) 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} x π \frac{7 π}{6} \frac{5 π}{4} \frac{4 π}{3} \frac{3 π}{2} \frac{5 π}{3} \frac{7 π}{4} \frac{11 π}{6} cos (x) - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2} 0 \frac{1}{2} \frac{2}{2} \frac{3}{2}

x = \frac{2 π}{3} + 2 πn, x = \frac{4 π}{3} + 2 πn

x = \frac{2 π}{3} + 2 πn, x = \frac{4 π}{3} + 2 πn

作图

流行的例子

-4sqrt(3)=12tan(θ)

- 43 = 12 tan (θ)

tan (2 θ) = 2.4

3sin^2(θ)=2sin(θ)+3

3 sin^{2} (θ) = 2 sin (θ) + 3

(sin(180)}{20}=\frac{sin(a))/8

\frac{sin ( 18 0 ^{\circ} )}{20} = \frac{sin ( a )}{8}

(sin(x)+cos(x))^2=1^2

(sin (x) + cos (x))^{2} = 1^{2}